Title: MAT. Potències
Course: Matemàtiques de 3r d'ESO

Feedback shared by this category's questions, if right: La resposta és correcta.
Feedback shared by this category's questions, if partly right: La resposta és parcialment correcta.
Feedback shared by this category's questions, if wrong: La resposta és incorrecta.

Q: Marca les igualtats correctes
- $$8^3\cdot 2^3=16^3$$
- $$8^3+2^3=10^3$$
- $$\frac{8^3}{2^3}=4^3$$
- $$8^3-2^3=6^3$$
- $$8^3\cdot 8^2=8^6$$
- $$8^3\cdot 8^2=8^5$$
- $$\frac{8^4}{8^7}=8^{-3}$$
- $$\frac{8^4}{8^7}=\frac{1}{8^3}$$
A: $$8^3\cdot 2^3=16^3$$; $$\frac{8^3}{2^3}=4^3$$; $$8^3\cdot 8^2=8^5$$; $$\frac{8^4}{8^7}=8^{-3}$$; $$\frac{8^4}{8^7}=\frac{1}{8^3}$$
If partly right: 1

Q: $$\frac{{a}^{4}}{{a}^{-3}}$$
- -1.3333
- {a}^(-7)
- {a}^(-4)
- {a}^(-3)
- {a}^(-1.333)
- {a}^(-4/3})
- {a}^1.333
- {a}^(4/3)
- {a}^3
- {a}^4
- {a}^7
- {a}^12
- {a}^1
- {a}^(-1)
A: {a}^7 (formula; values not in the backup's text)

Q: $$\frac{{a}^{{p}}}{{a}^{{q}}}$$
- {a}^{={p}-{q}}
- {a}^{={p}+{q}}
- {a}^{={p}/{q}}
- {a}^{={p}*{q}}
- {a}^{={q}/{p}}
- {a}^{={q}-{p}}
- {={a}*{p}}/{={a}*{q}}
- 1^{={p}-{q}}
- 1^{={p}/{q}}
A: {a}^{={p}-{q}} (formula; values not in the backup's text)
If right: La teva resposta és correcta.
If partly right: La teva resposta és parcialment correcta.
If wrong: La teva resposta és incorrecta.

Q: $$\frac{(a^{-2} b)^{-4}b^3}{(a^4)^{-2} b}$$.
- $$\frac{1}{b^2}$$
- $$\frac{1}{b}$$
- $$\frac{a}{b}$$
- $$\frac{a^8}{b^{-1}}$$
- $$\frac{a^8}{b^{-2}}$$
- $$\frac{a^8}{b}$$
- $$\frac{a^{11}}{b^4}$$
- $$\frac{a^{16}}{b^2}$$
A: $$\frac{a^{16}}{b^2}$$

Q: $$\frac{(a^2 a^{-3})^2 a^7}{a^5}$$.
A: 1
Partly right: a^0 (30%)

Q: $$(4a)^2=16a^2$$.
- Vertader
- Fals
A: Vertader

Q: $$(a+4)^2=a^2+16$$.
- Vertader
- Fals
A: Fals

Q: $$\left( \frac{7}{9}\right)^{-2}$$. (Marqueu l'opció més simplificada)
- $$\frac{-14}{-18}$$
- $$\frac{49}{81}$$
- $$\frac{18}{14}$$
- $$\frac{81}{49}$$
- $$\frac{-49}{-81}$$
- $$\frac{14}{18}$$
A: $$\frac{81}{49}$$

Q: $$5^{-3}$$.
- $$-125$$
- $$-5^3$$
- $$-15$$
- $$\frac{1}{5^3}$$
- $$-\frac{1}{5^3}$$
A: $$\frac{1}{5^3}$$

Q: $$\frac{5^3}{5^4}=$$
A: 5^-1 / 5^(-1) / 5⁻1 / 5⁻¹ / 1/5

Q: $$\frac{x^8}{x^3}=$$
A: x^5 / x⁵

Q: $$5^2\cdot 5^4=$$
A: 5^6 / 5⁶

Q: $$\frac{{a}^{{p}} \cdot {{a}}^{{q}}}{{a}^{{r}}}$$
- {a}^{={p}+{q}-{r}}
- {a}^{={p}*{q}/{r}}
- {a}^({={p}}*{={q}}/{={r}})
- {a}^{={p}+{q}+{r}}
- {a}^{={p}*{q}*{r}}
- {a}^{={p}+{q}+{r}}
- {={a}*{p}+{a}*{q}-{a}*{r}}
- {a}^{={p}+{q}-2*{r}}
A: {a}^{={p}+{q}-{r}} (formula; values not in the backup's text)
If right: La teva resposta és correcta.
If partly right: La teva resposta és parcialment correcta.
If wrong: La teva resposta és incorrecta.

Q: $$3^0$$
- 1
- 2
- 3
- 30
A: 1

Q: Indica la potència resultant: $$5^{-2}$$
A: 1/5^2 / 1/(5^2)
Feedback: $$a^{-n}=\frac{1}{a^n}$$

Q: Indica la potència resultant: $$5^{-2}$$
A: 1/5^2 / 1/(5^2) / 1/25
Feedback: $$a^{-n}=\frac{1}{a^n}$$

Q: Indica la potència resultant: $$(3^2)^5$$
A: 3^10
Feedback: $$(a^m)^n=a^{m\cdot n}$$

Q: $${a}^{p}\cdot {a}^{q}$$
- {a}^{={p}+{q}}
- {a}^{={p}*{q}}
- {={a}*{a}}^{={p}+{q}}
- {={a}*{a}}^{={p}*{q}}
- {={a}+{a}}^{={p}+{q}}
- {={a}+{a}}^{={p}*{q}}
A: {a}^{={p}+{q}} (formula; values not in the backup's text)

Q: $$\frac{{a}^{p}}{ {a}^{q}}$$
- {a}^{={p}-{q}}
- {a}^{={p}/{q}}
- 1^{={p}-{q}}
- 1^{={p}/{q}}
- {={a}+{a}}^{={p}-{q}}
- {={a}+{a}}^{={p}/{q}}
A: {a}^{={p}-{q}} (formula; values not in the backup's text)

Q: $$({a}\cdot{b})^{p}={a}^{p}\cdot {b}^{p}$$
- Vertader
- Fals
A: Vertader

Q: $$\({a}^{p}\)^{q}$$
- {a}^{=pow({p},{q})}
- {a}^{={p}+{q}}
- {a}^{={p}*{q}}
- {={a}*{p}}^{q}
A: {a}^{={p}*{q}} (formula; values not in the backup's text)

Q: $$({a}+{b})^{p}={a}^{p}+{b}^{p}$$
- Vertader
- Fals
A: Fals

Q: $$({a}+{={a}+{b}})^{p} = {a}^{p}+{={a}+{b}}^{p}$$
- Vertader ({={a}-{a}+1})
- Fals ({={a}-{a}})
A: Fals ({={a}-{a}}) (formula; values not in the backup's text)

Q: $${a}^{p}+{a}^{q}$$
- {a}^{={p}+{q}}
- {a}^{={p}*{q}}
- {=2*{a}}^{={p}+{q}}
- {=2*{a}}^{={p}*{q}}
- No es pot simplificar en una sola fracció
A: No es pot simplificar en una sola fracció

Q: $$\(\frac{{a}}{{b}}\)^{p}=\frac{{a}^{p}}{{b}^{p}}$$
- Vertader ({={a}-{a}+1})
- Fals ({={a}-{a}})
A: Vertader ({={a}-{a}+1}) (formula; values not in the backup's text)

Q: $$\frac{{a}^{p}}{{a}^{q}}$$
- 2*{a}^{p}
- {a}^{{p}*{q}}
- {a}^{={p}+{q}}
- 1^{={p}/{q}}
- {a}^{={q}-{p}}
- {=2*{a}}^{={p}+{q}}
- 1^{={p}-{q}}
- 1^{={p}/{q}}
- {a}^{={p}-{q}+1}
- {a}^{=-{p}-{q}}
- {a}^{={p}-{q}}
- {a}^{-{p}/{q}}
- {a}^{=-{q}/{p}}
- {a}^{p}
A: {a}^{={p}-{q}} (formula; values not in the backup's text)

Q: $$\frac{{a}^{p}}{{a}^{q}}$$
- {=2*{a}}^{p}
- {a}^{{p}*{q}}
- {a}^{={p}+{q}}
- 1^{={p}/{q}}
- {a}^{={p}-{q}+9}
- {=2*{a}}^{={p}+{q}}
- 1^{={p}-{q}}
- 1^{{p}/{q}}
- {a}^{={p}-{q}+1}
- {a}^{=-{p}-{q}}
- {a}^{={p}-{q}}
- {a}^{-{p}/{q}}
- {a}^{=-{q}/{p}}
- {a}^{p}
A: {a}^{={p}-{q}} (formula; values not in the backup's text)

Q: $$\frac{{a}^{{p}}}{{a}^{q}}\cdot {a}^{{r}}$$
- {=2*{a}}^{p}
- {a}^{{p}/{q}*{r}}
- {a}^{={p}+{q}}
- 1^{={p}/{q}*{r}}
- {a}^{={p}+{q}+{r}}
- {=3*{a}}^{={p}+{q}+{r}}
- 1^{={p}-{q}+{r}}
- 3^{{p}/{q}}
- {a}^{={p}-{q}+1}
- {a}^{=-{p}-{q}}
- {a}^{={p}-{q}+{r}}
- {a}^{-{p}/{q}}
- {a}^{=-{q}/{p}}
- {=3*{a}}^{={p}-{q}+{r}}
- {={a}*{a}}^({={p}*{r}}/{q})
A: {a}^{={p}-{q}+{r}} (formula; values not in the backup's text)

Q: Calculeu SENSE calculadora $${{a}}^{{n}}$$
A: pow({a},{n}) (formula; values not in the backup's text)

Q: Calculeu SENSE calculadora $$3^0$$
- 0
- 1
- 2
- 3
- 30
- No existeix
A: 1

Q: Calculeu SENSE calculadora $$2^3$$
A: 8

Q: $$2^x=16$$

Quin és el valor de x?
A: 4

Q: $$10^x={=pow(10,{s})}$$

Quin és el valor de x?
A: {s} (formula; values not in the backup's text)

Q: Calculeu SENSE calculadora $$1^{{n}}$$
A: {n}/{n} (formula; values not in the backup's text)

Q: Calculeu SENSE calculadora $${=pow(10,{n})}^{x}$$
A: pow(10,{n}*{x}) (formula; values not in the backup's text)

Q: Calculeu SENSE calculadora $${a}^1$$
A: {a} (formula; values not in the backup's text)

Q: Tinc {n} torretes. A cada torreta creixen {n} rosers. Cada roser té {n} branques. A cada branca han crescut {n} flors. Quantes flors hi ha en total?
A: pow({n},4) (formula; values not in the backup's text)

Q: $$(-{a})^{=2*{n}}$$
A: pow({a},2*{n}) (formula; values not in the backup's text)

Q: $$(-{a})^{=2*{n}+1}$$
A: -pow({a},2*{n}+1) (formula; values not in the backup's text)

Q: $$(-{a})^{=2*{n}+1}$$
A: pow({a},2*{n}+1) (formula; values not in the backup's text)

Q: $$(-1)^{{=2*{n}}}$$
A: 1+{n}-{n} (formula; values not in the backup's text)

Q: $$(-1)^{{=2*{n}+1}}$$
A: -1+{n}-{n} (formula; values not in the backup's text)

Q: $$-{a}^{=2*{n}}$$
A: -pow({a},2*{n}) (formula; values not in the backup's text)

Q: $$(+10)^{{=2*{n}+1}}$$
A: pow(10,2*{n}+1) (formula; values not in the backup's text)

Q: $$(-10)^{{=2*{n}}}$$
A: pow(10,2*{n}) (formula; values not in the backup's text)

Q: $$(-10)^{{=2*{n}+1}}$$
A: -pow(10,2*{n}+1) (formula; values not in the backup's text)

Q: $$10^x={=pow(10,-{s})}$$

Quin és el valor de x?
A: -{s} (formula; values not in the backup's text)

Q: $$10^x=0,0000001$$

Quin és el valor de x?
A: -7

Q: $$10^x=0,00001$$

Quin és el valor de x?
A: -5

Q: $$10^x=0,00000000000000001$$

Quin és el valor de x?
A: -17

Q: $$10^x=0,000000000000001$$

Quin és el valor de x?
A: -15

Q: Calcula $$10^{a}$$
A: pow(10,{a}) (formula; values not in the backup's text)

Q: Calcula $$10^{{a}}$$
A: pow(10,{a}) (formula; values not in the backup's text)

Q: Calcula $$10^{-{{a}}}$$
A: pow(10,-{a}) (formula; values not in the backup's text)

Q: Calcula $$10^{-{a}}$$
A: pow(10,-{a}) (formula; values not in the backup's text)